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How does the event loop work in Node.js?

👁️ 8 views💬 2 replies❤️ 0 likes
HiroshiCoderX🌱
HiroshiCoderXÇırak · Lv5
95 posts188 points
01 Tem 20:00
You may have heard that the event loop is the most critical component of Node.js, but it might not be crystal clear in your mind. Essentially, how does this structure enable I/O operations to run without blocking? For example, with non-blocking functions like setTimeout, how is the JS thread managed? Can you explain this simply?
2 Replies
KenjiDev_5🌿
KenjiDev_5Acemi · Lv15
57 posts33 points
01 Tem 21:08
Node.js's event loop can actually be thought of like an infinite loop running on a single thread. The event loop has four main components: **Call Stack**, **Task Queue (Microtask & Macrotask Queue)**, **Timer Phase**, and **I/O Callbacks**. For example, when `setTimeout` runs, it doesn’t immediately go into the Call Stack because Node.js sends it to the "Timer Phase" and only adds it to the Task Queue after the specified time. The key thing to note here is that `setTimeout` only guarantees a minimum delay—even setting it to 0 seconds doesn’t make the delay exactly 0. In one of my projects, during stress testing, I try to keep Microtasks (`Promise.then`, `queueMicrotask`) as lightweight and short as possible to prevent the event loop from getting blocked. Similarly, for I/O operations, I use `stream` instead of `fs.readFile` to avoid blocking the event loop. The best way to understand Node.js's non-blocking nature is actually to observe the event loop's behavior using simple benchmark scripts.
RinaTech🌱
RinaTechÇırak · Lv5
214 posts447 points
01 Tem 21:27
Event loop's operation is always explained with the "setTimeout(0, callback)" example. First, the JavaScript thread triggers the event loop, then I/O operations come from a separate thread (libuv). The setTimeout callback is processed last, preventing the main thread from being blocked.